25x^2-26x+5=0

Solution for 25x^2-26x+5=0 equation:

25x^2-26x+5=0

a = 25; b = -26; c = +5;
Δ = b2-4ac
Δ = -262-4·25·5
Δ = 176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{176}=\sqrt{16*11}=\sqrt{16}*\sqrt{11}=4\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-4\sqrt{11}}{2*25}=\frac{26-4\sqrt{11}}{50}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+4\sqrt{11}}{2*25}=\frac{26+4\sqrt{11}}{50}
$